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Lead Problem Does it depend on methods?
#1
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Posted 2016-October-22, 12:21
An opening lead problem; matchpoint pairs:
Adam W. Meyerson
a.k.a. Appeal Without Merit
a.k.a. Appeal Without Merit
#2
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Posted 2016-October-22, 14:57
♣
♠
♠
♠
♠
"Genius has its own limitations, however stupidity has no such boundaries!"
"It's only when a mosquito lands on your testicles that you realize there is always a way to solve problems without using violence!"
"Well to be perfectly honest, in my humble opinion, of course without offending anyone who thinks differently from my point of view, but also by looking into this matter in a different perspective and without being condemning of one's view's and by trying to make it objectified, and by considering each and every one's valid opinion, I honestly believe that I completely forgot what I was going to say."
"It's only when a mosquito lands on your testicles that you realize there is always a way to solve problems without using violence!"
"Well to be perfectly honest, in my humble opinion, of course without offending anyone who thinks differently from my point of view, but also by looking into this matter in a different perspective and without being condemning of one's view's and by trying to make it objectified, and by considering each and every one's valid opinion, I honestly believe that I completely forgot what I was going to say."
#3
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Posted 2016-October-22, 17:47
2h
openers known suit and my longest, best suit.. not dummies.
openers known suit and my longest, best suit.. not dummies.
#4
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Posted 2016-October-22, 18:40
spade, spade, spade. It's matchpoints. Let's not give anything away.
"Injustice anywhere is a threat to justice everywhere."
#6
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#7
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Posted 2016-October-23, 04:04
I'd lead J♦ on the first, which feels about as likely to give a trick away as a club and marginally more likely to hit an establishable five-card suit (given P couldn't double Stayman, which he might have scraped with Axxxx and something outside). Other than that, spade.
The "4♥ is a transfer to 4♠" award goes to Jinksy - PhilKing
#8
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Posted 2016-October-23, 04:44
Spade on all three explanations.
#9
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Posted 2016-October-24, 22:52
At the end of the auction, North mentioned that there had been a failure to alert, and that 2NT did not guarantee a four-card major. After this, West lead ♣K face down on the table. East then asked if 2NT could ever include a four-card major, and North said that it could not. Of course, the club king lead was not a success.
It seems that there was some amount of misinformation here (there's a difference between 2NT "may or may not have four spades" vs. 2NT "denies four spades") but according to the poll here it does not much effect people's leads. The director was not called at the table; I'm curious what the ruling would've been.
Adam W. Meyerson
a.k.a. Appeal Without Merit
a.k.a. Appeal Without Merit
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I rank
If LHO promises 4♠s, then ♦, ♣, ♠. ♥.
if LHO might have 4♠s, then ♠, ♦, ♣, ♥.
If LHO denies 4 M, then ♠, ♦, ♣, ♥.
For many partnerships this sequence would deny 4♠s with LHO (whether or not opponents remember their agreement), so a ♠ lead seems safe and normal except when this sequence explicitly promises 4♠s.