Vulnerable sacrifice or just defend?
#1
Posted 2014-August-06, 15:53
♠xx
♥AKxxx
♦Q872
♣Jx
(2♣)-2♦-(2♥)-3♦
(4♠)-Pa-Pa-???
wyman, on 2012-May-04, 09:48, said:
rbforster, on 2012-May-20, 21:04, said:
My YouTube Channel
#2
Posted 2014-August-06, 15:55
wyman, on 2012-May-04, 09:48, said:
rbforster, on 2012-May-20, 21:04, said:
My YouTube Channel
#3
Posted 2014-August-06, 16:22
Invariably, the ox on the left just trots out their suit at the five level, which is exactly what you want.
#5
Posted 2014-August-06, 21:07
PhilKing, on 2014-August-06, 16:22, said:
Invariably, the ox on the left just trots out their suit at the five level, which is exactly what you want.
So, he would be an oxy moron?
BTW, I would bid 5D over 2H also...but not positive it is a sacrifice. Certainly am not fond of 3D, then 5D, with any holding.
#7
Posted 2014-August-07, 03:09
PhilKing, on 2014-August-06, 16:22, said:
Invariably, the ox on the left just trots out their suit at the five level, which is exactly what you want.
Only true in a weak game.
But I agree, if you are tempted to bid 5♦ now, you should have done it on the previous round.
Rainer Herrmann
#9
Posted 2014-August-07, 08:48
whereagles, on 2014-August-07, 01:10, said:
I (perhaps falsely) assumed partner's 2D bid to look different than your partner's 2D bid in this situation.
#10
Posted 2014-August-07, 09:03
#13
Posted 2014-August-07, 09:20
How do you feel when you want to bid 4M but opps bid 5m before? well that's what should had happened.
#14
Posted 2014-August-07, 09:27
whereagles, on 2014-August-07, 09:09, said:
xxx
x
KJTxxx
Qxx
Yes, at RED, that is exactly what I am saying. 2D takes up no room; Partner knows Opener will be bidding 4M; and, there would be no earthly reason to bid 2D except to encourage partner to bid at the 5-level.
This post has been edited by aguahombre: 2014-August-07, 12:03
#15
Posted 2014-August-07, 13:38
steve2005, on 2014-August-06, 19:09, said:
It appears natural, but agree I want to know, and would ask immediately.
-gwnn
#17
Posted 2014-August-07, 16:26
#18
Posted 2014-August-07, 17:05
whereagles, on 2014-August-07, 16:26, said:
Just pretend you are playing 1$/2$ poker and raise the size of the pot. Nobody playing "Benji" will come up with the correct counter (if there is one) more than one time in two.