Thanks. I think it comes down to deciding East's shapes consistent with the bidding against which we can succeed. If East is void in
♥ there is no play. We'll ignore that. If East holds
♥x, then West holds
♥Q9xxxx (an ill-advised double at best). But a
♥ singleton does not allow us to clear
♥s with no losers. East must hold exactly 2
♥s. Before we play to trick 3 we know East likely held
♦A and
♣KQ. East knows that North is 5=5 or possible 6-5 so it would seem imprudent for East to double without the
♠Qxx. We also want West to hold at least 3
♦. A doubleton
♦ is a live possibility for West. (East can count so a
♦ would have hit the table at trick 2 if West had a singleton). So I think the hands are something like:
The
♣ switch takes our non-trump entry to dummy away. Winning the
♣A we lead the
♥3 to the
♥A and ruff a
♥ low.
♠2 to the
♠K then 2 top
♦s, pitching
♥s. Now the
♥10 should reveal the trump situation. If East plays small, I will finesse.
There is an inference that singletons attract singletons and balanced hands attract even splits. Righty wants us to finess lefty for the trump Q so let's not do that. (Righty revealed 9 HCP in the first 2 tricks.)
I still find West's double odd. Tell me what I am missing.