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〖专家金指〗持强牌如何显示对同伴低花的支持 一个极重要的叫牌

#1 User is offline   lycier 

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Posted 2013-January-27, 01:11



南家,持强牌如何显示对同伴低花的支持?


这是一个极重要的叫牌进程 !
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#2 User is offline   3ntmk 

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Posted 2013-January-27, 04:46

先应叫了1M后如何显示对同伴低花支持,我不太清楚。但这个进程可以跳到4D表示强的支持,同时也是低花木。
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#3 User is offline   lycier 

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Posted 2013-January-27, 05:35

这个进程很难,我在等待大家伙的讨论,然后在具体谈谈,而且都带有约定性的。
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#4 User is offline   wuhuan 

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Posted 2013-January-28, 02:29

同意3NTMK老师观点————跳叫4D低花木
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#5 User is offline   601821297 

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Posted 2013-January-28, 03:13

我认为无将老师的说法是对的 :)
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#6 User is offline   lycier 

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Posted 2013-January-28, 04:20

View PostTWO4BRIDGE, on 2013-January-19, 10:52, said:

Looking at my file notes, I found this same problem from a different Message board about 8 years ago.

It was suggested for the Diam case :
1D - 1S
2D - 3D = GF with only 4 cards and concern about .
Note that Responder can't have 4 cards either because with 4-4 he would have bid 1H first .
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Likewise for:
1D - 1H
2D - 3D = GF with only 4 cards and concern about .
If Responder also had 4 cards , he would have reversed into 2S .

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The Club case doesn't have a rebid "space" problem :
1C - 1M
2C - 2D! ( cheapest bid new suit forcing analogous to NMF over a 1NT rebid )

BBO论坛太好了,这也是我一直的心病,看到世界各国的高手们的意见,让人大看眼界,感觉自己真的很初级,知道的看到的总是那么一点点皮毛而已.....
关于此类话题,我总结出三类主流意见:

第一是TWO4BRIDGE意见:


1-关于再叫的建议:

1D - 1S
2D - 3D = 逼局,只有4张,对 担忧。
注意:应叫人不可能有4张,因为果如4-4高花,那应叫人应叫的是1首先。

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

2-同理可证:

1D - 1H
2D - 3D = 逼局,只有4张,对 担忧。
如果应叫人也有4张,他会逆叫2

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

3-关于的序列,就不存在再叫的空间问题。

1C - 1M
2C - 2D! (2 是最便宜的新花逼叫,类似于再叫1nt后,应叫人的新低花逼叫。 )


第二是lowerline的意见:

View Postlowerline, on 2013-January-21, 04:08, said:

This is what I play:

1 - 1

2 - 2 (inv+ relay)

Then:
2 = 4crd (2nt or 3 next can be passed)
2nt = 6 max GF
3 = 64 (3 next can be passed)
3 = 6 min NF
3 = 46 GF
3 = 36 GF

The issue with the invitational major 2suiter remains of course. But you have already given the solution for those.

Steven



这是我的叫牌方式:

1 - 1

2 - 2 (邀请+接力)

那么:
2 = 4张 (应叫人再叫2nt or 3 不逼叫,可以pass。)
2nt = 6 高限,逼局 。
3 = 6+4 (应叫人再叫3 不逼叫,可以pass。)
3 = 6 低限,不逼叫。
3 = 46 逼局。
3 = 36 逼局。

第三是以fluffy,phil和3ntmk为代表的意见:

View PostPhil, on 2013-January-18, 17:34, said:

2 is the standard solution. 4 is also possible.

A few non-standard:

1. Include 4cM's in your inverted minors.

2. Play 3 here as a one round force.

3. Start with a Rexfordesque 2!c.



View PostFluffy, on 2013-January-22, 06:42, said:

I would always take 4 as a slam try.

I would bid 2 and then 3 as a forcing raise, specially playing MPs,


世界大师fluffy意见:
我会永远把4 作为满贯试探。
而我先叫2,然后再叫3 作为逼局性加叫。

View Post3ntmk, on 2013-January-27, 04:46, said:

先应叫了1M后如何显示对同伴低花支持,我不太清楚。但这个进程可以跳到4D表示强的支持,同时也是低花木。

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#7 User is offline   nathan2008 

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Posted 2013-January-28, 04:42

用流行的 加叫低花逼叫得话,为什么不先2D? S 有44 总归有办法叫出来的。只有先2d 才有可能更容易上 6D。
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#8 User is offline   lycier 

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Posted 2013-January-28, 04:54

View PostTWO4BRIDGE, on 2013-January-19, 09:13, said:

I don't know if it is standard but it is certainly an option .

2H! = cheapest new bid suit forcing ( replies analogous to NMF over 1NT rebid ) and may be artificial.
But what if Opener has 4 cards and you don't ( as here ) ?

1D - 2S
2D - 2H!
3H - ?? now what ??



而phil和fluffy的意见,遭到了TWO4BRIDGE强大的反戈一击:

如果这是标准方案,我不知晓,但我认为这不过是一个选择而已。
假设说,果如你所言:2H! = 最便宜的新花逼叫叫品,也许是个约定叫。
但是!当开叫人有4张,而你并没有,看看下面序列吧:


1D - 2S
2D - 2H!
3H - ?? 请问您现在如何处理?
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#9 User is offline   madongjun 

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Posted 2013-January-28, 05:57

嗯,这个如何处理后面是加了两个??的。
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#10 User is offline   lycier 

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Posted 2013-January-28, 06:11

是的,加叫同伴最便宜的高花,永远都是四张加叫的。这是叫牌法则。
所以,遭到了强烈的反击。
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#11 User is offline   zyp163 

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Posted 2013-January-28, 10:31

如果没有人为设计叫品,我认为:
基于5542体系。
1D-1H/1S
2D-3D
这个3D是逼叫性,承诺到4D水平的。
原因:
1.开叫人叫2D未否认有另一高花四张。他只是因牌力低限不能叫而已。
2.1H/1S应叫是高花优先,开叫人2D表示低限了,在无成局希望的情况下,何必自加一级定约?

基于以上观点:
1D-1H/1S
2D-4D
这个4D正如3NTMK老师所讲,是有满贯意愿的,即使定义为关键张问叫也合理。

5542框架下的1C我没想好。我宁愿把1C开叫当成0NT开叫。
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#12 User is offline   lycier 

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Posted 2013-January-28, 20:27

View Postzyp163, on 2013-January-28, 10:31, said:

如果没有人为设计叫品,我认为:
基于5542体系。
1D-1H/1S
2D-3D
这个3D是逼叫性,承诺到4D水平的。
原因:
1.开叫人叫2D未否认有另一高花四张。他只是因牌力低限不能叫而已。
2.1H/1S应叫是高花优先,开叫人2D表示低限了,在无成局希望的情况下,何必自加一级定约?

基于以上观点:
1D-1H/1S
2D-4D
这个4D正如3NTMK老师所讲,是有满贯意愿的,即使定义为关键张问叫也合理。

5542框架下的1C我没想好。我宁愿把1C开叫当成0NT开叫。

你对3的自愿加叫,理由不是充分。这里面争议很大的。我还可以说你的自愿3是不逼叫的邀请呢。也不是没有专家认为:自愿加叫3d做逼局,是不标准的,phil就是这个意见。
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#13 User is offline   yunling 

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Posted 2013-February-21, 07:03

第一轮就叫2C(C套或者均型逼局)吧。把这种牌往本来就拥挤不堪的1D-1M序列里塞实在是勉为其难。
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#14 User is offline   hejiang 

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Posted 2013-March-31, 20:20

低花配合,但又不符合低花加叫(有四张高花)的强牌,如何合理既做到逼叫又显示配合确实有点难,止于3NT吧又不甘心,想探冠吧也许只有3NT是最佳定约。想起独孤狐曾经教过的高拉蒂,处理这类问题确实有独到之处。
1--2(首先建立一个进局显示,不否定四张高花,留下空间进一步描述)
3--3(3是降级显示有5张以上,3显示配合)
后续处理起来就相对比较简单,好处在于:
1、首先不担心丢局
2、在3阶上已知高花不配,低花配合
3、为后续叫牌留下空间
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#15 User is offline   dillon561 

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Posted 2013-March-31, 22:12

View Postlycier, on 2013-January-28, 20:27, said:

你对3的自愿加叫,理由不是充分。这里面争议很大的。我还可以说你的自愿3是不逼叫的邀请呢。也不是没有专家认为:自愿加叫3d做逼局,是不标准的,phil就是这个意见。

是的,我也认为,不是邀请,就单是阻击都可能.如果你们没进局力量,但如果你D有配合的话,停在2D,下家很可能就会发现问题进行平衡争叫,根据总赢墩定律,你如果有3+D,联手9+张D了,最好叫上3阶封住下家口,让他冒3阶叫牌的风险.所以3D也可以就是个阻击叫品.这在很多精确牌手比赛时可看出,他们就是知道没局了就想尽可能低停在1,2阶,结果引出别人争到一个不成局定约.
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#16 User is offline   00master 

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Posted 2013-March-31, 22:12

这牌叫4作为罗马关键张问叫后,同伴答叫4表示1个关键张时,你是赌6还是停在5?这总是猜断。
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#17 User is offline   wuhuan 

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Posted 2013-March-31, 22:23

不论制定出什么样的约定,这副牌的软肋在C套上,论坛里的高人现在越拉越多,
恳请定出一套在开叫1D后开叫、应叫方均能显示出C上有控制的约定最好。
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#18 User is offline   yzdhy668 

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Posted 2013-April-01, 16:54

赞同3NT老师的4D低花木叫品。
按照哈代2/1体系应叫再叫3D是邀请牌力,新花是逼叫但再叫2H描述不准确,用3C逼叫我认为更合适。

1D - 1S
2D - 3C 用新低花作为逼局。
3X - 4D 再用4D作为低花木问关键张
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#19 User is offline   yzdhy668 

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Posted 2013-April-02, 04:03

看到一个资料对开叫人2D再叫后的应叫是这样描述的
1D - 1S
2D - ?
① 2H :S/H5-4以上,通常低限。
② 2S :S较好5张以上,通常低限。
③ 2N :9+~11-HCP,邀叫,其它花色有止。
④ 3C :12+HCP,S通常5张以上,至少逼局。(新低花逼叫)
⑤ 3D :9+~11-HCP,S4张以上,D3张以上,不合适再叫2N。
⑥ 3H :12+HCP,S/H5-5以上。
⑦ 3S :9+~11-HCP,S6张以上好套。
⑧ 3N :自然。
⑨ 4D :D为将的关键张问叫。
⑩ 4H:D为将的排除性关键张问叫。
⑾ 4S :自然止叫。
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#20 User is offline   670922 

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Posted 2013-April-02, 07:57

是不是先逼叫,新高花
。后在叫出支持。再问关键张,?
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