[Kungsgeten]

Zelandakh, on 2013-January-24, 09:00, said:

What is 3♠ Kungsgeten? It seems impossible that this would be an invite with the given hand. Can North splinter over 2♠ or would that show the 17+ hand?

3S would be a natural and invitational, but you're right, north would probably bid 4S right away. 4C would have been a splinter bid, not implying the strong hand. 2NT would have been a GF relay.

[Zelandakh]

If a 4♣ splinter can be made with the 0-7 hand type then it seems to me to be clearly indicated on the North hand. That would allow you to find rare low-HCP slams that noone else would get close to. If you do not do it with this hand then you may as well specify it as a void splinter instead.

[Mbodell]

1♥X E

1♣-1♦(1♥) : 16+ unbal OR 18+ bal; 0-7 or occ 8+ with <2 ctls
X-All pass : take-out; converted

[qplus10]

1♣1♥(it seems to like giving a positive when it is close)
3nt

3nt won the split on the mp score. 1nt is beta 2nt is 16+ forcing balanced and 3nt is 16+ may have a singleton.

[jack502]

1♣2♥
4♠

2♥=semi positive 5+ hearts 4 spades.

[FM75]

OCP

1♣ - 1♦ (1♥)
2N - 3N

[Lord Molyb]

I'm not pro enough to end up defending 1♥x

Molybdenum Forcing Pass System:
S ---- N
P --- 1♣ (1♥) (opening hand, 0-bad 12)
dbl --- 2♠ (4+ ♠ and pretty much anything else, 6-9 points and 4 spades )
4♠ --- P (signoff)

FM75, on 2013-February-11, 17:10, said:

OCP

1♣ - 1♦ (1♥)
2N - 3N

How do you find spades with that system?
What do those bids mean?

[CamHenry]

Unnamed Homebrew Diamond:
2♣-2♦ weak ♦ OR weak majors OR GF majors OR 20-23 bal / pass-or-correct
2N-2♦ 20-23 bal / transfer ♥
3♥-3♠ denies 4-card support / also 4 ♠
4♦-4♥ 5 or 7 CPs, agreeing ♠ / interest in slam opposite 7
5♣-5♠ second-round ♣ control / signoff as there is ♣ duplication

[Zelandakh]

CamHenry, on 2013-February-25, 14:05, said:

Unnamed Homebrew Diamond:
4♦-4♥ 5 or 7 CPs, agreeing ♠ / interest in slam opposite 7
5♣-5♠ second-round ♣ control / signoff as there is ♣ duplication

South has 6 CPs (1 ace and 4 kings). What would South bid over 4♥ with first round club control instead of second?

[CamHenry]

Zelandakh, on 2013-February-26, 03:59, said:

South has 6 CPs (1 ace and 4 kings). What would South bid over 4♥ with first round club control instead of second?

(i) we count the trump Q as a control
(ii) after establishing that we may have enough CPs for slam (11 for small, 13 for grand), we bid 2nd-round controls up the line. If duplication is found, we sign off. Obviously with 6 facing 6, for example, we can ignore the first point of duplication (K facing singleton).
(iii) I miscounted N's controls; on the actual hand he's only got 3 CPs (DA, C singleton) and would therefore sign off in 4♠

Let's modify the hands a little to

T943
JT965
AK3
9

AKQ8
KQ
Q974
A85

Here S still has 7 CPs (2 aces at 2 each, 2 kings at 1 each, trump Q at 1) and N now has 4 (A, K, singleton). The auction, from S making a slam try in S, would be:
4♦-4♥ 5 or 7 CPs, agreeing ♠/interest in slam opposite 7
5♥-6♠ Second-round ♥ control, no 2nd-round control in either minor, 7 CPs/7 facing 4, no duplication, => 11 working CPs, a fit, and hopefully enough for slam.

I hope this illustration is a little clearer!

[Zelandakh]

CamHenry, on 2013-February-26, 06:23, said:

I hope this illustration is a little clearer!

Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of ♦A and ♣x. First of all, that you count a singleton as 1CP and secondly if that means the ♦K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before.

[CamHenry]

Zelandakh, on 2013-February-26, 06:38, said:

Excellent description! Yes, that is much clearer. The point I am still slightly unsure of is when you say that North has 3 CPs consisting of ♦A and ♣x. First of all, that you count a singleton as 1CP and secondly if that means the ♦K is not worth anything. Finally, there is a the question as to how you find duplication opposite a void. This is certainly an interesting method though - not one I have come across before.

First off, in the original hand N has 3CPs as he doesn't have the ♦K. We count singletons as 1 CP.

As for voids: we also count those as singletons if responding to the slam try. We try not to make a slam try of this type when holding a void: there are many different enquiries we can make (e.g. Exclusion, etc.; on some sequences we have cue-bidding available).

Full system notes are available at http://www.matthew.a...systemnotes.pdf - the section on this slam method is at p.34 (General Swiss). We picked it up from another player at the Cambridge Bridge Club (I think we tweaked it a bit, but I can't remember).

[Zelandakh]

Thanks for this link. The write-up is very clear and the approach is interesting. It is (kind of) a little like Turbo but with CPs instead of key cards. Hopefully it will come up on a few of the upcoming hands so we can see it in action. For the strong 2-suited openings, you could take a look at Ben (inquiry)'s MisIry method if you wanted to add some extra detail/complexity to the follow-ups.

[PrecisionL]

Upgraded Ultra Club Relay (C3)

1♣ - 1♦ (1♥)
X for TO - 1♠ (hearts are not good enough for penalty pass) -
2♠ - 4♠ All Pass