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forcing?

#1 User is offline   kgr 

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Posted 2012-April-07, 05:18

Question triggered by other post.
Are following sequences forcing and what do they show?:

(1C)-1H-(P)-1S

(1C)-1H-(2C)-2S

(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S

(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S

and how do you play these jumps?:
(1C)-1H-(Pas)-2S

(1C)-1H-(Pas)-3S

(1C)-1H-(2C)-3S

Remark: In fact we play transfer (1D transfer to H) and Rubens advances, but I don't think that makes a difference for the given sequences?
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#2 User is offline   mgoetze 

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Posted 2012-April-07, 05:31

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(P)-1S

Usually F but a minority play NF.

Quote

(1C)-1H-(2C)-2S

F West of Germany (USA, UK, France...), NF East of Germany (Poland etc.), needs agreement here.

Quote

(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S

Opposite of above.

Quote

(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S

Uhm... I dunno.

Quote

and how do you play these jumps?:
(1C)-1H-(Pas)-2S

(1C)-1H-(Pas)-3S

(1C)-1H-(2C)-3S

Fit, fit and fit, though I won't claim this is optimal.
"One of the painful things about our time is that those who feel certainty are stupid, and those with any imagination and understanding are filled with doubt and indecision"
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#3 User is offline   FrancesHinden 

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Posted 2012-April-07, 14:50

View Postkgr, on 2012-April-07, 05:18, said:

Question triggered by other post.
Are following sequences forcing and what do they show?:

(1C)-1H-(P)-1S


A matter of agreement, forcing or not forcing are both popular.

Quote

(1C)-1H-(2C)-2S

(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S


If the first is forcing the second one isn't, and vice versa. I play the first as non-forcing (even though I'm west of Germany) because the chance of having a non-forcing 2S bid is so much higher than the chance of having a forcing one.

Quote

(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S


Same as above

Quote

and how do you play these jumps?:
(1C)-1H-(Pas)-2S


If 1S is non-forcing, then this is natural and forcing. Otherwise it's fit.

Quote

(1C)-1H-(Pas)-3S

(1C)-1H-(2C)-3S


Fit
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#4 User is offline   gnasher 

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Posted 2012-April-07, 16:04

What Frances said, except

Quote

Quote

(1C)-1H-(Pas)-2S

If 1S is non-forcing, then this is natural and forcing.

I think it's reasonable to just not have a forcing spade bid at all. It's very rare that you have enough to insist on game when you don't have a fit, and when it does happen you may be able to get away with treating Hx as a fit, or just guessing the right game. With less than a game-force, it's usually OK to make a non-foricng 1 bid.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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#5 User is offline   kgr 

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Posted 2012-April-08, 02:30

These are our agreements for some and my own thoughts resulting from it:

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(P)-1S

Forcing by agreement

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(2C)-2S

Proposing to my partner that this is non-forcing

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S

Even if a direct 2S is non-forcing, I thought that this one could also be non-forcing?
Strong, but non-forcing. With a stronger hand you can now bid 3C or 3S?

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S

Forcing,

View Postkgr, on 2012-April-07, 05:18, said:

(1C)-1H-(Pas)-2S

(1C)-1H-(Pas)-3S

(1C)-1H-(2C)-3S
Fit-bids then?
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