Question triggered by other post.
Are following sequences forcing and what do they show?:
(1C)-1H-(P)-1S
(1C)-1H-(2C)-2S
(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S
(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S
and how do you play these jumps?:
(1C)-1H-(Pas)-2S
(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
Remark: In fact we play transfer (1D transfer to H) and Rubens advances, but I don't think that makes a difference for the given sequences?
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forcing?
#2
Posted 2012-April-07, 05:31
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(P)-1S
Usually F but a minority play NF.
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(1C)-1H-(2C)-2S
F West of Germany (USA, UK, France...), NF East of Germany (Poland etc.), needs agreement here.
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(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S
(Pas)-2D-(Pas)-2S
Opposite of above.
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(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S
(Pas)-2D-(3C)-3S
Uhm... I dunno.
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and how do you play these jumps?:
(1C)-1H-(Pas)-2S
(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
(1C)-1H-(Pas)-2S
(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
Fit, fit and fit, though I won't claim this is optimal.
"One of the painful things about our time is that those who feel certainty are stupid, and those with any imagination and understanding are filled with doubt and indecision"
-- Bertrand Russell
-- Bertrand Russell
#3
Posted 2012-April-07, 14:50
kgr, on 2012-April-07, 05:18, said:
Question triggered by other post.
Are following sequences forcing and what do they show?:
(1C)-1H-(P)-1S
Are following sequences forcing and what do they show?:
(1C)-1H-(P)-1S
A matter of agreement, forcing or not forcing are both popular.
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(1C)-1H-(2C)-2S
(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S
(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S
If the first is forcing the second one isn't, and vice versa. I play the first as non-forcing (even though I'm west of Germany) because the chance of having a non-forcing 2S bid is so much higher than the chance of having a forcing one.
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(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S
(Pas)-2D-(3C)-3S
Same as above
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and how do you play these jumps?:
(1C)-1H-(Pas)-2S
(1C)-1H-(Pas)-2S
If 1S is non-forcing, then this is natural and forcing. Otherwise it's fit.
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(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
(1C)-1H-(2C)-3S
Fit
#4
Posted 2012-April-07, 16:04
What Frances said, except
If 1S is non-forcing, then this is natural and forcing.
I think it's reasonable to just not have a forcing spade bid at all. It's very rare that you have enough to insist on game when you don't have a fit, and when it does happen you may be able to get away with treating Hx as a fit, or just guessing the right game. With less than a game-force, it's usually OK to make a non-foricng 1♠ bid.
Quote
Quote
(1C)-1H-(Pas)-2S
If 1S is non-forcing, then this is natural and forcing.
I think it's reasonable to just not have a forcing spade bid at all. It's very rare that you have enough to insist on game when you don't have a fit, and when it does happen you may be able to get away with treating Hx as a fit, or just guessing the right game. With less than a game-force, it's usually OK to make a non-foricng 1♠ bid.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
#5
Posted 2012-April-08, 02:30
These are our agreements for some and my own thoughts resulting from it:
Forcing by agreement
Proposing to my partner that this is non-forcing
Even if a direct 2S is non-forcing, I thought that this one could also be non-forcing?
Strong, but non-forcing. With a stronger hand you can now bid 3C or 3S?
Forcing,
Fit-bids then?
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(P)-1S
Forcing by agreement
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(2C)-2S
Proposing to my partner that this is non-forcing
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(2C)-DBL
(Pas)-2D-(Pas)-2S
(Pas)-2D-(Pas)-2S
Even if a direct 2S is non-forcing, I thought that this one could also be non-forcing?
Strong, but non-forcing. With a stronger hand you can now bid 3C or 3S?
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(2C)-DBL
(Pas)-2D-(3C)-3S
(Pas)-2D-(3C)-3S
Forcing,
kgr, on 2012-April-07, 05:18, said:
(1C)-1H-(Pas)-2S
(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
(1C)-1H-(Pas)-3S
(1C)-1H-(2C)-3S
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