I had this one today:
pass-1♣
1♠ - 2♣
2♦-pass
2-4 fit, not a success, who is the missbidder?
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How forcing is forcing extension
#2
Posted 2011-January-10, 18:43
depends on agreement but unless 2♦ is specifically agreed as artificial, it must logically be non-forcing. of course the question is how many spades and how many diamonds? that again is a question of agreement, perhaps you reply 1♠ always with weak hands and 4-6 in the pointeds, in which case the misbid was 2♦; perhaps you bid up the line in which case responder is only showing 5-4, then probably opener should pull to 2♠. but maybe it should show 5-5 - fishing for a 4-4 here is wishful
... and I can prove it with my usual, flawless logic.
George Carlin
George Carlin
#3
Posted 2011-January-11, 00:46
Hi,
For us 2D would be 3rd suit / NMF, so it would be forcing.
Playing natural methods - 2-4 fit sounds, as if the 2D bidder had only 2 diamonds,
2D is certainly nonforcing, but should show inv. values, and 5 spades.
With kind regards
Marlowe
For us 2D would be 3rd suit / NMF, so it would be forcing.
Playing natural methods - 2-4 fit sounds, as if the 2D bidder had only 2 diamonds,
2D is certainly nonforcing, but should show inv. values, and 5 spades.
With kind regards
Marlowe
With kind regards
Uwe Gebhardt (P_Marlowe)
Uwe Gebhardt (P_Marlowe)
#6
Posted 2011-January-13, 15:08
I think it's invitational-only fourth suit forcing. Never agreed how forcing it is but I suppose it could make sense to have everything by opener to be nonforcing.
... and I can prove it with my usual, flawless logic.
George Carlin
George Carlin
#7
Posted 2011-January-14, 04:10
I think all these bids show the same hand-type as by a non-passed hand playing natural methods, with the range adjusted. That is:
- If you bid spades and then bid diamonds, you're showing 5+ spades, 4+ diamonds, and invitational values.
- If you bid fourth-suit, it shows invitational values, no known 8-card fit, and no stop in the unbid suit. Logically, opener's continuations are non-forcing, because both players are limited, responder's hand is quite well defined, and we might be too high already.
- If you bid spades and then bid diamonds, you're showing 5+ spades, 4+ diamonds, and invitational values.
- If you bid fourth-suit, it shows invitational values, no known 8-card fit, and no stop in the unbid suit. Logically, opener's continuations are non-forcing, because both players are limited, responder's hand is quite well defined, and we might be too high already.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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