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ha?

#1 User is offline   gwnn 

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Posted 2010-May-19, 19:01

p-1C-p-1H
x-2c-2d-2s

shows 2+c and 4+h
... and I can prove it with my usual, flawless logic.
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#2 User is offline   arigreen 

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Posted 2010-May-20, 14:52

This is kind of a strange auction -- LHO has implied length in spades, partner has denied 4 spades. I would think that 2♠ here shows values in spades but not necessarily a 4-card suit. I don't think it should promise any clubs though.
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