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suit combination restricted choice

#1 User is offline   tkass 

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Posted 2009-May-05, 09:43

qx in front of ak98xx

on the queen play the jack appear behind the ak98xx

is it a clear restricted choice?

some people on web say most of the club player will falsecard the jack with dbl j10 so when the jack appear play the drop, when the 10 appear finesse.


i wanna know what is the correct play?

thx tkass
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#2 User is offline   manudude03 

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Posted 2009-May-05, 09:46

J could have easily been from JTx as well (mandatory falsecard), so play for the drop. If I think my opps aren't capable of this, then I finesse.
Wayne Somerville
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#3 User is offline   rbforster 

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Posted 2009-May-05, 10:07

The only winning holding for the hook is J / Txxx when the J falls. Holdings where falsecards don't cost are Jx, Jxx, JTx, JTxx behind (although some of these assume partner would have covered the Q, hence declarer must have the AK). You'll also lose to half the JT tight cases behind when you play for the hook.

I think it's clearly restricted choice, but in this case there are lots of potential falsecards from 3-2 splits that make it unattractive hook if you think the falsecards are sufficiently likely.
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#4 User is offline   1eyedjack 

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Posted 2009-May-05, 13:08

manudude is right.

The only combinations you need to consider is H singleton, HH doubleton or HHx tripleton offside. There are other possibilities as RobF posts, but in any other case you are either destined to fail or destined to succeed whichever play you make, and most of the time it will be apparent which from the card played to the second trick in front of the Ace.

The next question is: what is the frequency with which he should play H from HHx to make the finesse and drop equal odds? (in a vacuum, of course - in reality there will probably be additional information)
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#5 User is offline   manudude03 

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Posted 2009-May-05, 13:34

A. Txxx/J = 2.823%
B. xxx/JT= 1/2 x 3.39 = 1.695%
C. xx/JTx= 1/2 x 10.174= 5.087%

P(falsecardC)xC=A-B

5.087P=1.128
P= 0.2217 or 22.2%

This is assuming they will play the J and T at equal probabilities.
Wayne Somerville
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