♣♦♥♠
The
ACBL Bulletin has an example (final column in the article).
In this one,
♠s are agreed as trump, RKCB yada yada, then Queen-ask, then Queen-answer = no (i.e. askee returns to 5
♠), and asker passes 5
♠.
Just prior to the example, another example has a response of 5
♥ to RKCB (i.e. 2 KC's without the Queen). THe author explains "Well, we're either missing a black ace and the Queen of trumps, or the King and Queen of trumps; either way slam's not a great idea. So we'll park it in five."
If parking in five is a good idea when we're off a Keycard and the Queen, doesn't it make sense to use the Q-ask to find out if that's true or not?
http://web2.acbl.org/documentLibrary/play/...omankeycard.pdf
If Q-ask promises all 5 keycards, then it must be a GS try. I admit to never having heard of that.... if that's the case, then surely there must be some literature on the web that explains how the Q-ask is always a try for a GS?
NB - Here's an article by Fred on (gasp!) MSN gaming zone. (How the hell did THAT happen????)
http://zone.msn.com/...gblackwood1.htm
Quoting .... (Emphasis added)..
"There are three important points to remember about asking for the Queen of trump. The first one is pretty obvious, but it should still be mentioned:
1. Do not ask for the Queen of trump if you hold that card!
2. Sometimes the Queen ask takes the partnership above five of the agreed trump suit (for example when Hearts is the agreed suit and 5 Diamonds is the response to RKCB).
In this case, the Queen ask promises that the partnership holds all five keycards and that the 4NT bidder is interested in a possible grand slam.
3. Occasionally, it is correct to tell your partner you have the Queen of trump even when you don't! For example, if you partner opens 1 Spade playing five-card majors, and later bids RKCB after Spades are agreed, it is correct to show the Queen of trump anytime you have five or more Spades! The reason for this is that the Queen of trump is usually not relevant when the partnership holds 10 or more cards in the trump suit. Even if the trump suit is as weak as:
A 9 8 7 6 opposite K 5 4 3 2
There is almost an 80% chance that the opponents' trump will divide two to one."
Gee, Fred, are you moonlighting for the competition now ?
This post has been edited by ralph23: 2007-August-09, 11:01