Jlall, on Jul 18 2007, 01:01 PM, said:
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Logically, I figured that if you'd try for game with a 5431 16 count after
1♥ 1♠ P 2♠ P
you would also try for game with a 5431 16 count after
1♠ 2♣ 2♠ P
Am I wrong?
No. I never said this was not the case. WTF is your point?
My point is that I see both auctions as primarily obstructive. The object here is to make the opponents make the last guess. the objective is not to find find game, unless partner has an extreme hand.
My point is that I think that a 3+244 4 count with one ace and a 2+254 well supported 7 count with one ace are about equal in offense. If you don't think that's true, then up the point value to where they're equal, there's nothing magical about 7. While the auctions are not the same, partner's going to invite with the same hand in both cases. I think that if anything, partner should expect a weaker hand from 1
♥ 1
♠ P 2
♠ because the bid may be the best of a bad set of choices, while after 1
♠ 2
♣ 2
♠ you had both pass and X available to you.
My point was that if you can see the parallel strengths of the hands, and the parallel objectives in bidding the two hands, then hopefully you can see where I'm coming from. I obviously was not successful.
On the auction 1
♥ 1
♠ P, would you bid 2
♠ with 9xx xx Axxx 8xxx?
If the answer is yes, then the parallels between the two bids should be obvious. If the answer is no, then the parallels don't immediately apply, but it doesn't make a lot of sense to me.
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That is because you are equating 2 non similar auctions from different threads and looking at only one aspect of my argument.
That the best bid combined with the best bid can get you to a bad place? I thought that was self-evident.
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1) When you have 2 trumps and a random 7 count then getting to the 3 level in the 5-2 fit is pretty much a disaster.
Cohen's rule is 'eight never, nine ever'. I was going to grab more quotes to explain where I was coming from, but I never got the chance.
I agree that getting to the three level in a 5-2 to fit would be a disaster. However, if you follow Cohen's rule, the original overcaller will never bid 3
♠ without 6 cards in the suit. If the raise can be two cards, then it's extra sure that the original overcaller will never bid 3
♠ without 6 cards in the suit. So you may end up in a 6-2, which violates Cohen's rule, but never a 5-2.
Take the 5431 16 count across the 2254 7 count. If the singleton is in opener's suit, then to try for game the overcaller bids 3 of his longer minor, and now you're playing in a 4-4 or a 5-4 fit. If the overcaller instead has the singleton in a minor and the opponent's suit well stopped, he bids 2NT, and with a 23 count and a fit in the minors that's hardly a horror. If the overcaller doesn't have shortness in opener's suit but doesn't have the stoppers for NT, he can pass or bid the minor. Game tries, in other words, are easily handled without any real loss. What else were you using those bids for?
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2) You cannot take arguments as a whole and then zone in on one aspect of that argument and compare it to the same aspect from another thread.
The others aspects I think I can argue through pretty easily. This is the only negative aspect I'm worried about.
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I have stated already that I think raising with 2 trumps is bad because it will cause partner to misjudge. He may try for game assuming we have a fit and upgrading for that. He may misjudge a competitive auction. We may get to the wrong strain. These are all downsides.
Let's start with the idea that you're not fooling partner. Partner's going to assume you have three cards, but he's aware that you might have 2 and will factor that into the auction when it doesn't cost anything. That you've discussed this possibility before the game. Surprising partner is a bad thing regardless.
A) Trying for game: I don't think that partner trying for game assuming a fit is a problem as long as the minimum for two card support is signifanctly stronger than the minimum for 3 card support. If partner thinks we have 21+ hcp and a 5-3 fit, I don't think it'll be a disaster when we turn up with 24+ hcp and a 5-2 fit. Obviously, partner can't just bid 3
♠ with 5, but there are far cheaper ways to try for game.
Misjudging a competitive auction: I think this is far more likely to happen to the opponents. Overcaller has already shown 5, there is no reason for him to show it again. If you follow the eight never principle, overcaller shouldn't be tempted to compete further with 5. If partner things we're 6-3 and we're actually 6-2, this can be an issue, sure. But the opponents don't even have that much information. If opener has 6, can he be sure partner has 2? If responder has 3, can he be sure partner has 6? 6-2 is not a bad fit.
C) Wrong strain: I think it's actually tougher to get to another strain without the raise. Obviously, if it gets passed out, you're not finding another strain. After the raise, you can afford to show an alternate strain if you also have interest in game. After 1
♥ 1
♠ P P 2
♥, can you even find 3NT when it's right? I doubt I could.
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If you still do not understand why I think raising with 2 trumps and random hands is a good idea, you never will.
Yeah, I get it. It's the same old argument used for everything from not opening a weak 2 without 2 of the top 3 honors to 1
♦-1
♠-2
♠ with 3 card support to overcalling with 4 card suits to your call. How many times can you name where you've gotten that same argument from somebody else?
But if you start thinking about the LOTT and eight never, you can see why raising with 2 card support with certain hands fits with those rules and doesn't cause major problems. These hands are not random- that's why you don't do it with 2344 shape, or with the same minimum strength that you'd bid it with 3 card support.